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本帖最后由 小草 于 2024-3-27 08:32 编辑
D(2n)的密度系数
D(2n)的密度系数与2n的数因子有着密切的关系.表D(2n)=C*2n/ln^2(2n),这时C=∑(1,k_)Cpk.Cpk有时虽然是负的,但是它的极限值且是正的.所以当2n→∞时,Cpk是一个正常数,C=∑(1^,k_)Cpk也是一个正常数,且C*2n/ln^2(2n)→∞.
我们有:2^3=8,D(2^3)=8*0.54050964065797660275049034211751/ln^2(8)=1,3>1;
2^4=16,D(2^4)=16*0.96090602783640284933420505265333/ln^2(16)=2,4>2;
2^5=32,D(2^5)=32*0.75070783424718972604234769738544/ln^2(32)=2,5>2;
2^6=64,D(2^6)=64*1.3512741016449415068762258552937/ln^2(64)=5,6>5;
2^7=128,D(2^7)=128*0.55177025817168444864112555757829/ln^2(128)=3,7>3;
2^8=256,D(2^8)=256*0.96090602783640284933420505265335/ln^2(256)=8,8=8;
2^9=512,D(2^9)=512*0.83610085039280755737966474796301/ln^2(512)=11,9<11;
2^10=1024,D(2^10)=1024*1.0322232720898858733082280839049/ln^2(1024)=22,10<22;
2^11=2048,D(2^11)=2048*0.70965349956179653789940680768463/ln^2(2048)=25,11<25.
当n→∞时,k=o(D(2n)),所以C2=Cp1→a1,a1是一个常数.
C3(6)=0.05461398534319880456108532098148,
C3(12)=-0.02594621914459130089810033407568,
C3(18)=-0.03265615018709559580545950942333,
C3(24)=0.30159724073725324046859971757267
C3(30)=0.30159724073725324046859971757267
C3(36)=0.67613749711654421856615322876966
C3(42)=0.67613749711654421856615322876966
C3(48)=0.81035438105013075978581910259036
C3(54)=0.72262491795135593542393479724326
C3(60)=0.72262491795135593542393479724326
C3(66)=0.72262491795135593542393479724326
C3(72)=0.1728819894833792073344834642376
C3(78)=0.1728819894833792073344834642376
C3(84)=0.1728819894833792073344834642376
C3(90)=0.1728819894833792073344834642376
C3(96)=0.1678188242997454953288573337966
C3(102)=0.1678188242997454953288573337966
C3(108)=0.2726038856151882217468774648536
C3(114)=0.2726038856151882217468774648536
C3(120)=0.2726038856151882217468774648536
C3(126)=0.2726038856151882217468774648536
C3(132)=0.2726038856151882217468774648536
C3(138)=0.2726038856151882217468774648536
C3(144)=1.3349622873773949914843044719084
C3(150)=1.3349622873773949914843044719084
C3(156)=1.3349622873773949914843044719084
当2n→∞时,C3=Cp2,所以Cp2→a2,a2是一个常数.
可知对于所有的Cpk,Cpk→ak,ak是一个常数.
当n→∞时,C2(2^n)<C2(2^n-1),但D(2^n)>D(2^n-1).
4=2^2
C2(4)=0.48045301391820142466710252632669
D(4)=4*0.48045301391820142466710252632669/ln^2(2^2)=1
6=2*3
C2(6)=0.48045301391820142466710252632669
C3(6)=0.05461398534319880456108532098148
D(6)=6*0.53506699926140022922818784730817/ln^2(6)=1
8=2^3
C2(8)=0.54050964065797660275049034211751
D(2^3)=8*0.54050964065797660275049034211751/ln^2(8)=1
10=2*5
C2(10)=0.54050964065797660275049034211751
C5(10)=0.51986998143770299936184293560129
D(10)=10*1.0603796220956796021123332777188/ln^2(10)=2
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