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本帖最后由 朱明君 于 2024-1-17 13:21 编辑
一,\(设\ x^a+y^b=z^c{,}\ 其中\ x{,}y{,}z{,}a{,}b{,}c{,}n为正整数,\)
\(则\left( xz^{nb}\right)^a+\left( yz^{na}\right)^b=z^{nab+c}\)
二,\(设\ x^a+y^b=z^c{,}\ 其中\ x{,}y{,}z{,}a{,}b{,}c{,}n{,}为正整数,\)
\(若a是nb的倍数,则\left( xz\right)^a+\left( yz^n\right)^b=z^{a+c}\)
三,\(设\ x^n+y^{n+1}=z^n,其中\ x{,}y{,}z{,}n{,}K为正整数,\)
\(\left( 2^n-1\right)^n+\left( 2^n-1\right)^{n+1}=\left( 2\left( 2^n-1\right)\right)^n\)
\(则\left( xK^{n+1}\right)^n+\left( yK^n\right)^{n+1}=\left( zK^{n+1}\right)^n\)
(第1题)
\(解方程x^{202401}+y^3=z^{202403}\)
\(原方程,1^a+2^3=3^2{,}\ \ 其中a为大于等于1的正整数,\)
\(若a是nb的倍数,则\left( xz\right)^a+\left( yz^n\right)^b=z^{a+c}\)
\(设a=202401,\ 代入公式得\)
\(\left( 1\times3^1\right)^{202401}+\left( 2\times3^{67467}\right)^3=3^{202403}\)
(第2题)
\(解方程x^3+y^4=z^5\)
\(原方程,2^3+1^b+=3^2{,}\ 其中b为大于等于1的正整数,\)
\(则\left( xz^{nb}\right)^a+\left( yz^{na}\right)^b=z^{nab+c}\)
\(设b=4, \ n=4, \ 代入公式得\)
\(\left( 2\times3^{16}\right)^3+\left( 1\times3^{12}\right)^4=\left( 3^{10}\right)^5\)
(第3题)
\(解方程x^n+y^{n+1}=z^n{,}\ \ 其中x,y,z,n为正整数,\)
\(且2^n-1=x=y{,}\ \ 2\left( 2^n-1\right)=z{,}\)
\(一,则\left( 2^n-1\right)^n+\left( 2^n-1\right)^{n+1}=\left( 2\left( 2^n-1\right)\right)^n\)
\(二,则\left( xK^{n+1}\right)^n+\left( yK^n\right)^{n+1}=\left( zK^{n+1}\right)^n\)
\(设n=4{,}\ 代入公式一得\left( 2^4-1\right)^4=\left( 2^4-1\right)^5=\left( 2\left( 2^4-1\right)\right)^4\)
\(设n=3{,}\ \ K=4{,}\ \ 代入公式二得\left( \left( 2^3-1\right)\times4^4\right)^3+\left( \left( 2^3-1\right)\times4^3\right)^4=\left( \left( 2^3-1\right)\times4^4\right)^3\) |
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