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发表于 2021-11-28 11:18
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本帖最后由 愚工688 于 2021-11-28 04:04 编辑
10个连续偶数的真值:
3112513550:10:2
G(3112513550) = 6318397
G(3112513552) = 4741462
G(3112513554) = 9520337
G(3112513556) = 4943757
G(3112513558) = 6319921
G(3112513560) = 13788790
G(3112513562) = 4740315
G(3112513564) = 4739433
G(3112513566) = 9928144
G(3112513568) = 4740742
count = 10, algorithm = 2, working threads = 2, time use 0.723 sec
你的计算:
D(3112513554)=3121904*3=9365712;Δ≈-0.01624;
D(3112513556)=4682857;Δ≈-0.05277;
D(3112513558)=4682857 ;Δ≈-0.25903;——为什么这个偶数的相对误差会这么大?因为它含有素因子7、11 。
D(3112513560)=3121904*4=12487616;Δ≈-0.09436;
D(3112513562)=4682857;Δ≈-0.01212;
你的计算值的相对误差的波动时比较大的,因为你没有考虑√M的全部素因子的作用。只有考虑√M的全部素因子的作用,像全息摄影那样不放过造成素对数量波动的每个素数,才能比较好的反应出素对数量的真实情况。
因为你的计算值都小于真值,我也使用素对下界计算式来进行计算10个连续的偶数:
G(3112513550) = 6318397;
inf( 3112513550 )≈ 6294817.6 , Δ≈-0.00373 ,infS(m) = 4721113.17 , k(m)= 1.33333
G(3112513552) = 4741462;
inf( 3112513552 )≈ 4721113.2 , Δ≈-0.00429 ,infS(m) = 4721113.17 , k(m)= 1
G(3112513554) = 9520337;
inf( 3112513554 )≈ 9481733.6 , Δ≈-0.00405 ,infS(m) = 4721113.18 , k(m)= 2.00837
G(3112513556) = 4943757;
inf( 3112513556 )≈ 4924396.5 , Δ≈-0.00392 ,infS(m) = 4721113.18 , k(m)= 1.04306
G(3112513558) = 6319921;
inf( 3112513558 )≈ 6294817.6 , Δ≈-0.00397 ,infS(m) = 4721113.18 , k(m)= 1.33333
G(3112513560) = 13788790;
inf( 3112513560 )≈ 13734952.9 , Δ≈-0.00390 ,infS(m) = 4721113.19 , k(m)= 2.90926
G(3112513562) = 4740315;
inf( 3112513562 )≈ 4721498.6 , Δ≈-0.00397 ,infS(m) = 4721113.19 , k(m)= 1.00008
G(3112513564) = 4739433;
inf( 3112513564 )≈ 4721113.2 , Δ≈-0.00387 ,infS(m) = 4721113.19 , k(m)= 1
G(3112513566) = 9928144;
inf( 3112513566 )≈ 9890847 , Δ≈-0.00376 ,infS(m) = 4721113.19 , k(m)= 2.09502
G(3112513568) = 4740742;
inf( 3112513568 )≈ 4721113.2 , Δ≈-0.00414 ,infS(m) = 4721113.2 , k(m)= 1
inf( 3112513570 )≈ 6309091.6 , Δ≈,infS(m) = 4721113.2 , k(m)= 1.33636
inf( 3112513572 )≈ 11330671.7 , Δ≈,infS(m) = 4721113.2 , k(m)= 2.4
time start =10:43:17 ,time end =10:44:27 ,time use |
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