若 n^2+(n+1)^2 是素数,
则 7 是素数 n^2+(n+1)^2 的原根。
----------------------------------------------------
{{12,8},{17,12},{39,8},{47,8},{162,10},{222,10},{407,8},{927,8},{1067,14},{1212,8},{1317,10},{1517,10},{1802,10},{1832,8},{2112,8},{2187,8},{2507,8},{2612,8},{2682,10},{2712,8},{2882,10},{3237,11},{3347,8},{3392,8},{3522,10},{4182,11},{4772,8},{4952,11},{5027,8},{5967,8},{5997,10},{6387,8},{6662,10},{6917,10},{7127,8},{7617,10},{7682,10},{7892,8},{8202,10},{8237,10},{8342,10},{8397,12},{8492,8},{8622,10},{8762,10},{8802,10},{9087,8},{9642,12},{9992,12},{10442,10},{11397,10},{11457,10},{12057,10},{12762,10},{12827,8},{12857,10},{12962,10},{13077,10},{13182,12},{13697,10},{14057,12},{14187,8},{14862,10},{15062,10},{15447,8},{15522,10},{15587,8},{15872,8},{15942,11},{16217,10},{16367,8},{16532,8},{16542,10},{17267,8},{17897,10},{18152,8},{18497,10},{19337,10},{19482,10},{19517,10}} |