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费马大定理成立的一句话解读。

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发表于 2010-10-4 23:17 | 显示全部楼层 |阅读模式
````````````````费马大定理成立的一句话解读。
````正整数n≥2,Z^n-x^n-y^n=0,````````````````````````````````````````````````````(1)
适合其底数的充分条件者,显然是某些三角形三边长Z>x∧>y、x+y>Z所代表的正实数。如此,据勾股定理,给出任意正实数Z(代表直径长也就是代表一切三角形的长边长),皆有直角三角形三边长对应
Z^2-x^2-y^2=0`` ```` ```` ```` ```` ```` ```` ```` ```` ```` ```` ```` ```` ``````````````(2)
成立;故据(2)和指数运算法则就同步判定:
正整数n>2,Z^n-x^n-y^n =0,``` ```` ```` ```` ```` ```` ```` ```` ```` ```` ```````````(3)
实际皆同一是表示
`` ``````````` ```Z^2*Z^`n-2`-x^2*x^`n-2`-y^2*y^`n-2`=
`` ````````` (x^2+y^2)Z^`n-2`-(x^2*x^`n-2`+y^2*y ^`n-2`)=
```` (x^2*Z^`n-2`+y^2*Z^`n-2`)―(x^2*x^`n-2`+y^2* y ^`n-2`)>0。` ````````````` ````` `````(4)
即证明(1)除写成(2)外,写成(3)只能用于表述大于0的不等式,自然也就无等式性正整数解。换言之,所谓费马方程,本质上是一个正实数假命题的子命题,故不成立。反过来说,费马大定理成立。
 楼主| 发表于 2010-10-5 16:23 | 显示全部楼层

费马大定理成立的一句话解读。

真言一句话,假传万卷书,洋八股的裹脚布可以休也。
 楼主| 发表于 2010-10-7 23:17 | 显示全部楼层

费马大定理成立的一句话解读。

[这个贴子最后由沟道效应在 2010/11/18 00:05pm 第 1 次编辑]

````附件
````````````用周明祥勾股弦二元函数式验证(3)无正整数解的摘录。
````据2010年7月15日第一版《迈向世界的中国科技》刊载周明祥鄢福荣著《基础数学的新发现与世界
近代数学三大难题》改撰为下述文本格式。
```` (1)的底若表示正整数,其诸子方程选择正整数的充分条件,显然皆应同一表示为:x≠y,
z>x,````````````z>y,`````````x+y>z。``````````````````````````````````````````(5)
同解得
(x+y)–z =2a,`````z–y = b,`````z–x = c, ```其中,b≠c,并可设2a=2tw。`→
z=2a+b+c=2tw+b+c,x=2a+b=2tw+b,y=2a+c=2tw+c。````````````````````````````````````` (6)
````n=2,将(6)代入(2)得正整数底的c依附于b,可配方c=2t^2*w^2∕b,它们使方程成立为
(2tw+b+2t^2*w^2∕b )^2 = (2tw+b)^2 +(2tw+2t^2*w^2∕b)^2 ,```````````````````````(7)
是带参数w的三对应二元函数。其中,t∧b=1、2、…,当b是平方数参数w=√b, 否则,参数w=b。以t
作序数,b作谱号,其全部解组与平面坐标第1象限内整点--映射,可列成
````````````````````《带参数的三对应二元勾股弦函数谱阵排列》↓——(示意表)
`` b、w值:``b=1、w=1````b=2、w=2````b=3、w=3````b=4、w=2``……`` b=9、w=3```b=…
`````````````````````````````````````````````````````````````````````````````````````
t``三底数````x```y```z````x```y```z```x```y````z```x```y````z``……``x```y```z````…
序 与构造``2t+1``↓``↓``4t+2`↓``↓``6t+3``↓``↓`4t+4`↓``↓`……`6t+9`↓```↓```…
````子公式``2t+2t^2``↓```4t+4t^2`↓````6t+6t^2`↓``4t+2t^2`↓`……```6t+2t^2`↓``…
数```````````2t+1+2t^2````4t+2+4t^2`````6t+3+6t^2````4t+4+2t^2`……````6t+9+2t^2``…
↓勾股弦数 →```````````````````````````````````````````````````````````````````````
1````````↓`03``04``05```06``08``10```09``12``15```08``06``10``……``15``08``17```…
2```````````05``12``13```10``24``26```15``36``39```12``16``20``……``21``20``29```…
3```````````07``24``25```14``48``50```21``72``75```16``30``34``……``27``36``45```…
4```````````09``40``41```18``80``82```27`120`123```20``48``52``……``33``56``65```…
5```````````11``60``61```22`120`122```33`180`183```24``70``74``……``39``80``89```…
…``````````…``…``…```…``…``…```…``…``…```…``…``…``……``…``…``…```…
````n>2,把(6)代入(3)就得诸子式的最终真相,全都是实表示  n>2,Z^n-x^n-y^n =
( x^2*Z^`n-2`+y^2*Z^`n-2`)-(x^2*x^`n-2`+y^2* y^`n-2`)=
[(2a+b)^2 (2a+b+c )^`n-2`+(2a+c)^2 (2a+b+c )^`n-2`]-[(2a+b)^2 (2a+b)^`n-2`+(2a+c)^2 (2a+c)^`n-2`]>0。
这就是说,任何正整数c皆不可能使等式成立。(3)无正整数解被验证属真。
 楼主| 发表于 2010-11-18 10:56 | 显示全部楼层

费马大定理成立的一句话解读。

洋八股的长篇裹脚布可以休也。
发表于 2010-11-18 22:42 | 显示全部楼层

费马大定理成立的一句话解读。

下面引用由882907792010/11/18 07:57pm 发表的内容:
反过来说,洋八股的长篇裹脚布可能还有市场?
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发表于 2013-3-1 18:44 | 显示全部楼层

费马大定理成立的一句话解读。

楼主好像证得不错,顶起!
发表于 2013-3-5 12:01 | 显示全部楼层

费马大定理成立的一句话解读。

楼主,我想了很久,发现个问题:
楼主的(4)式不外乎证明了当n>2时,Z^n-Y^n-X^n>0,但是在条件Z^2=X^2+Y^2下得到的,那在Z^2≠X^2+Y^2的情况下,有没有可能当n>2时,Z^n-Y^n-X^n=0呢?所以我觉得楼主还没有证明了费马定理。
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