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楼主 |
发表于 2021-1-5 19:33
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使用连乘式计算连续偶数的素对下界值,看看计算值精度如何?
inf( 2021010500 )≈ 4262261.1 , jd ≈,infS(m) = 3188752.43 , k(m)= 1.33665
inf( 2021010502 )≈ 3827411.6 , jd ≈,infS(m) = 3188752.44 , k(m)= 1.20028
inf( 2021010504 )≈ 6377504.9 , jd ≈,infS(m) = 3188752.44 , k(m)= 2
inf( 2021010506 )≈ 3537103.6 , jd ≈,infS(m) = 3188752.44 , k(m)= 1.10924
inf( 2021010508 )≈ 3543058.3 , jd ≈,infS(m) = 3188752.45 , k(m)= 1.11111
inf( 2021010510 )≈ 8541132.5 , jd ≈,infS(m) = 3188752.45 , k(m)= 2.67852
inf( 2021010512 )≈ 3237810.2 , jd ≈,infS(m) = 3188752.45 , k(m)= 1.01538
inf( 2021010514 )≈ 3196587.2 , jd ≈,infS(m) = 3188752.46 , k(m)= 1.00246
inf( 2021010516 )≈ 7708867.3 , jd ≈,infS(m) = 3188752.46 , k(m)= 2.41752
inf( 2021010518 )≈ 3188752.5 , jd ≈,infS(m) = 3188752.46 , k(m)= 1
inf( 2021010520 )≈ 4369756.9 , jd ≈,infS(m) = 3188752.46 , k(m)= 1.37037
inf( 2021010522 )≈ 6937229.1 , jd ≈,infS(m) = 3188752.47 , k(m)= 2.17553
time start =19:28:36 ,time end =19:29:28 ,time use =
inf( 2021010500 ) = 1/(1+ .148 )*( 2021010500 /2 -2)*p(m) ≈ 4262261.1
inf( 2021010502 ) = 1/(1+ .148 )*( 2021010502 /2 -2)*p(m) ≈ 3827411.6
inf( 2021010504 ) = 1/(1+ .148 )*( 2021010504 /2 -2)*p(m) ≈ 6377504.9
inf( 2021010506 ) = 1/(1+ .148 )*( 2021010506 /2 -2)*p(m) ≈ 3537103.6
inf( 2021010508 ) = 1/(1+ .148 )*( 2021010508 /2 -2)*p(m) ≈ 3543058.3
inf( 2021010510 ) = 1/(1+ .148 )*( 2021010510 /2 -2)*p(m) ≈ 8541132.5
inf( 2021010512 ) = 1/(1+ .148 )*( 2021010512 /2 -2)*p(m) ≈ 3237810.2
inf( 2021010514 ) = 1/(1+ .148 )*( 2021010514 /2 -2)*p(m) ≈ 3196587.2
inf( 2021010516 ) = 1/(1+ .148 )*( 2021010516 /2 -2)*p(m) ≈ 7708867.3
inf( 2021010518 ) = 1/(1+ .148 )*( 2021010518 /2 -2)*p(m) ≈ 3188752.5
inf( 2021010520 ) = 1/(1+ .148 )*( 2021010520 /2 -2)*p(m) ≈ 4369756.9
inf( 2021010522 ) = 1/(1+ .148 )*( 2021010522 /2 -2)*p(m) ≈ 6937229.1 |
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