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方程素数判断,素数公式

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发表于 2024-5-23 11:23 | 显示全部楼层 |阅读模式
已知:整数\(a>0\),\(b>0\),\(m>0\),\(t>0\),\(a=\frac{c-1}{2}\),\(b=a^2-2c\),奇数\(c>9\),素数\(p>0\)
方程\(\frac{a\times\left( a+1\right)\times\left( bc+c-1\right)^3+m^2}{t}-c=0\),有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc+c\right)^3+c^2}{t}-c=0\),没有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc-c\right)^3+c^2}{t}-c=0\),没有整数解
求证:\(c=p\)
已知:整数\(a>0\),\(b>0\),\(m>0\),\(t>0\),\(c\ge m\)
\(a=\frac{c-1}{2}\),\(b=a^2-2c\),奇数\(c>9\),素数\(p>0\)
方程\(\frac{a\times\left( a+1\right)\times\left( bc+c-1\right)^3+m^2}{t}-c=0\),有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc+c\right)^3+c^2}{t}-c=0\),没有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc-c\right)^3+c^2}{t}-c=0\),没有整数解
求证:\(c=p\)
已知:整数\(a>0\),\(b>0\),\(h>0\),\(k>0\)\(m>0\),\(t>0\),\(c\ge m\),\(\frac{c}{3}\ne h\)
\(\frac{c}{5}\ne k\),\(a=\frac{c-1}{2}\),\(b=a^2-2c\),奇数\(c>9\),素数\(p>0\)
方程\(\frac{a\times\left( a+1\right)\times\left( bc+c-1\right)^3+m^2}{t}-c=0\),有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc+c\right)^3+c^2}{t}-c=0\),没有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc-c\right)^3+c^2}{t}-c=0\),没有整数解
求证:\(c=p\)
已知:整数\(a>0\),\(b>0\),\(m>0\),\(t>0\),\(a=\frac{c-1}{2}\),\(b=a^2-2c\),奇数\(c>9\),素数\(p>0\)
方程\(\frac{a\times\left( a+1\right)\times\left( bc-c-1\right)^3+m^2}{t}-c=0\),有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc+c\right)^3+c^2}{t}-c=0\),没有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc-c\right)^3+c^2}{t}-c=0\),没有整数解
求证:\(c=p\)
已知:整数\(a>0\),\(b>0\),\(m>0\),\(t>0\),\(c\ge m\)
\(a=\frac{c-1}{2}\),\(b=a^2-2c\),奇数\(c>9\),素数\(p>0\)
方程\(\frac{a\times\left( a+1\right)\times\left( bc-c-1\right)^3+m^2}{t}-c=0\),有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc+c\right)^3+c^2}{t}-c=0\),没有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc-c\right)^3+c^2}{t}-c=0\),没有整数解
求证:\(c=p\)
已知:整数\(a>0\),\(b>0\),\(h>0\),\(k>0\)\(m>0\),\(t>0\),\(c\ge m\),\(\frac{c}{3}\ne h\)
\(\frac{c}{5}\ne k\),\(a=\frac{c-1}{2}\),\(b=a^2-2c\),奇数\(c>9\),素数\(p>0\)
方程\(\frac{a\times\left( a+1\right)\times\left( bc-c-1\right)^3+m^2}{t}-c=0\),有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc+c\right)^3+c^2}{t}-c=0\),没有整数解
方程\(\frac{a\times\left( a+1\right)\times\left( bc-c\right)^3+c^2}{t}-c=0\),没有整数解
求证:\(c=p\)
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