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elim 发表于 2024-6-24 01:45 对\(m\in\mathbb{N}\)有\(N_{\infty}\subset A_m,\;A_m^c=\{k\in\mathbb{N}:k\le m\}\)即 \(H_{\infty}\cap ...
elim 发表于 2024-6-24 21:02 \((1)\;\;(N_{\infty}\subset A_m)\iff (N_{\infty}\cap A_m^c=\varnothing)\;(\forall m\in\mathbb{N})\) ...
elim 发表于 2024-6-25 09:08 \((0)\;\;A_m:=\{k\in\mathbb{N}: k> m\},\;N_{\infty}:=\displaystyle\bigcap_{n=1}^\infty A_n.\) \((1) ...
elim 发表于 2024-6-25 22:30 \(N_k = \displaystyle\bigcap_{m=1}^k A_m = A_k \ne\varnothing\). 蠢痴从 \(N_{\infty}=N_{\infty}\cap ...
elim 发表于 2024-6-26 11:14 蠢疯说:由于\(\displaystyle\bigcup_{m=1}^\infty A_m^c =\big(\bigcap_{m=1}^\infty A_m\big)^c\) 所以 ...
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